Quiz 1:

Q:

1) Find the solution to the following system of equations: P=25-Q and
P=5+3Q.

2) Fid the slope of x^{3}y=5.

A:

1) 25-Q=5+3Q since where the two line cross the Ps will be the same.

This gives 20=4Q or Q=5. Plug this back into either equation to find that
P=5+3(5)=20.

2)The slope is dy/dx. This can be found as -(df/dx)/(df/dy). For
this problem df/dx=3x^{2}y and dy/dx=x^{3}.

Hence the slope is -3x^{2}y/x^{3} = -3y/x.