1) Find the solution to the following system of equations: P=25-Q and P=5+3Q.
2) Fid the slope of x3y=5.
1) 25-Q=5+3Q since where the two line cross the Ps will be the same.
This gives 20=4Q or Q=5. Plug this back into either equation to find that P=5+3(5)=20.
2)The slope is dy/dx. This can be found as -(df/dx)/(df/dy). For
this problem df/dx=3x2y and dy/dx=x3.
Hence the slope is -3x2y/x3 = -3y/x.